1840 United States presidential election in Arkansas

A presidential election was held in Arkansas on November 2, 1840 as part of the 1840 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1840 United States presidential election in Arkansas

← 1836 November 2, 1840 1844 →

← PA CT →

Nominee Martin Van Buren William H. Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Mentor Johnson John Tyler Electoral vote 3 0 Popular vote 6,679 5,160 Percentage 56.42% 43.58%

Van Buren   50–60%   60–70%   70–80%   80–90%   90–100% Harrison   50–60%   60–70%   70–80%   80–90% Unknown/No vote

President before election Martin Van Buren Democratic Elected President William H. Harrison Whig

Arkansas voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Arkansas by a margin of 12.84%.

Results

1840 United States presidential election in Arkansas
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard Mentor Johnson of Kentucky	6,679	56.42%	3	100.00%
	Whig	William Henry Harrison of Ohio	John Tyler of Virginia	5,160	43.58%	0	0.00%
Total				11,839	100.00%	3	100.00%

See also

• United States presidential elections in Arkansas